It's stiffness, K, or spring constant if you will, per Hooke's Law F=kx, is. F=kx. k = F/x. k = F/ (FL^3/3EI) k = 3EI/L^3. which is the inverse of the deflection under a unit load. You are asking why, I think, you use the cantilever stiffness for a fixed pinned column in a frame with a load applied at the joint.

The force that a spring can produce on its stretching or compressing is known as a spring force. Spring Force depends on the spring stiffness and the deformation observed in the spring. Answer and ...

Yes, it's the stiffness of the spring. In the units you listed, kg / s 2, it is not intuitive, but that unit is equivalent to N / m, which is force per length.. So a spring with a k-value of 1 N/m requires one Newton to compress (or extend, depending on the spring) it by one meter.

Structure Stiffness Matrix y x 3 4 1 2 6 5 L 2 EI 1 EI 2 L 1!=#∆ The 6x6 structure stiffness matrix can be assembled from the element stiffness matrices Each beam joint can move in two directions: 2 Degrees of Freedom (DOF) per joint

Stiffness of a single interatomic "spring"? One mole of iron (6 x 10^23 atoms) has a mass of 56 grams, and its density is 7.87 grams per cubic centimeter, so the center-to-center distance between atoms is 2.28 x 10^-10 m.You have a long thin bar of iron, 2.8 m long, with a square cross section, 0.07 cm on a side. You hang the rod vertically and attach a 50 kg mass to the bottom, and you ...

Mathematically, Hooke's law is stated as: F =−kx F = − kx. where: x is the displacement of the spring's end from its equilibrium position (a distance, in SI units: meters); F is the restoring force exerted by the spring on that end (in SI units: N or kg·m/s 2 ); and. k is a constant called the rate or spring constant (in SI units: N/m ...

Answer (1 of 2): Stiffness Extension of a coil spring, δ, caused by an axial force, F Stiffness is the extent to which an object resists deformation in response to an applied force. [1] The complementary concept is flexibility or pliability: the more flexible an object is, the less stiff it i...

When the units of the spring stiffness are shown, the input will be converted based on the Display Units. When a DOF Spring uses different degrees-of-freedom at each node, the physical meaning of connecting a translation to a rotation are difficult to envision. Therefore, no units are shown for the spring stiffness, and no conversion is performed.

We already know that stiffness is directly related to deflection, but we still need to derive the formula. To do this, it's beneficial to remember that stiffness is typically represented as a spring constant, k. And we know that the spring constant is defined as force divided by deflection, which gives us the following formula: k= Fx